((-40+8x))/((28x-32-6x^2))=0

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Solution for ((-40+8x))/((28x-32-6x^2))=0 equation: 



((-40+8x))/((28x-32-6x^2))=0



Domain of the equation: ((28x-32-6x^2))!=0

x∈R



We add all the numbers together, and all the variables

((8x-40))/((28x-32-6x^2))=0

We multiply all the terms by the denominator


((8x-40))=0



We calculate terms in parentheses: +((8x-40)), so:

(8x-40)

We get rid of parentheses

8x-40

Back to the equation:

+(8x-40)



We get rid of parentheses

8x-40=0

We move all terms containing x to the left, all other terms to the right

8x=40

x=40/8

x=5

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